A bird flying outside a train (running at the speed of 110 km/h) finds it very difficult to match the train's speed. But when the same bird is flying inside the train's bogie, it is able to match the speed with with much less efforts. Explain why.
Dear student,
This is a case of stationary and moving frame of references. Train acts as a moving frame. When we are watching the bird which is outside, we are in the moving frame. But when the bird is inside the train we are in the same frame as the bird.
The bird that is flying outside the train has to use its own strength to match the train's speed the bird moves by beating it's wings against the air. while, when it is flying inside, it is also a passenger of the train. Thus, it can easily match the speed of the train The bird is flying in the air inside the closed train. As this air moves with the train (we don't feel the wind blow), the bird can just fly in the air in our frame of reference.
Regards
This is a case of stationary and moving frame of references. Train acts as a moving frame. When we are watching the bird which is outside, we are in the moving frame. But when the bird is inside the train we are in the same frame as the bird.
The bird that is flying outside the train has to use its own strength to match the train's speed the bird moves by beating it's wings against the air. while, when it is flying inside, it is also a passenger of the train. Thus, it can easily match the speed of the train The bird is flying in the air inside the closed train. As this air moves with the train (we don't feel the wind blow), the bird can just fly in the air in our frame of reference.
Regards