a block of mass 10 kg is pulled with a constant speed on a rough horizontal plane with a force of 19.6 n. the co-officient of friction is....?

We have, mass, m = 10 kg

If the coefficient of friction is µ, then the frictional force is, f = µmg

Since, the block is pushed with constant velocity it means the net force acting on it is zero. That means the applied force equals frictional force,

f = µmg = 19.6

=> µ(10)(9.8) = 19.6

=> µ = 0.2

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