A block of mass 5 kg is places on an inclined plane having angle of inclination 60°. A horizontal force of 50 N is applied on the block. Write the component of : 1) force. 2) weight. 3) along and perpendicular to the plane. Please give a detailed answer of this query as I couldn't understand the solution that was provided earlier.
Dear Student
Please see the figure below
Weight of block can be break into two components
(i) Along the plane: Mg sin 60
(ii) Perpendicular to the plane: Mg cos 60
Also there is normal force acting on the plane which acts perpendicular to the plane and balance perpendicular component of the weight of block.
As force is acting horizontal to block, so it can also be break into two components
(i) Along the plane: F cos 60
(ii) Perpendicular to the plane: F Sin 60
Regards
Please see the figure below
Weight of block can be break into two components
(i) Along the plane: Mg sin 60
(ii) Perpendicular to the plane: Mg cos 60
Also there is normal force acting on the plane which acts perpendicular to the plane and balance perpendicular component of the weight of block.
As force is acting horizontal to block, so it can also be break into two components
(i) Along the plane: F cos 60
(ii) Perpendicular to the plane: F Sin 60
Regards