A blue coloured crystalline salt 'A' on heating decomposes to 'B' a white substance . when in blue salt solution , a metal (Zinc) is added , its gives rise to colourless solution leaving behind 'D' reddish brown metal
(a) name the compounds A,B,C,D.
(b) Identify the type of reaction involved in the formation of 'C' and 'D"
Dear student
(a)The blue crystalline salt is copper sulphate pentahydrate.(A) It is blue in colour and its chemical formula is CuSO4.5H2O. When heated , it decomposes to a white substance , which is anyhdrous copper sulfate, CuSO4 (B). The reaction is:
(a)The blue crystalline salt is copper sulphate pentahydrate.(A) It is blue in colour and its chemical formula is CuSO4.5H2O. When heated , it decomposes to a white substance , which is anyhdrous copper sulfate, CuSO4 (B). The reaction is:
CuSO4.5H2O -----Heat---> CuSO4 + 5H2O
Zinc reacts slowly with copper(II) sulfate, it precipitates copper metal(D), which is a reddish brown metal and the zinc gets dissolved in the solution of copper sulfate to form zinc sulfate. (, which is C,{ in the question, it is not mentioned which compound should be taken as C }]
b)The reaction involved is :
Zn(s) + CuSO4(aq) → Cu(s) + ZnSO4(aq)
This is a displacement reaction.