a body drops a coin from top of a tower ..coin takes "t" seconds to come down from the top of a tower ...calculate time taken to cover half the hieght of the tower Share with your friends Share 1 Ravi Gupta answered this u = 0height of the tower is h.h = ut +12at2h = 0+gt22 --- (1)T is the time taken to cover the half height h2 = uT+12aT2h2 =12gT2 h =gT2 --- (2)FROM (2) AAND (1) WE GETgT2 =gt22T = t2 4 View Full Answer Swagat Swargari answered this let height of the tower = x m here, initial velocity, u =0 time = t sec so, x = ut + 1/2 at2 x = 0 + 1/2 at2 a = 2x /t2 at x/2 distance x/2 = 0 + 1/2 * 2x / t2 * T2 T2 = x/2 * t2 /x T2 = t2 /2 T = t / root 2 T = t * root 2 / root 2*root 2 T = (t/2) root 2 sec 0
