A body is revolving in a vertical circle with constant mechanical energy.the speed of the body at the highest point is root over 2gr.the speed of the body at the lowest point is??



Applying principle of conservation of energy between L and H, we have12mvL2=12mvH2+mg2rWe have given, vH=2gr 12mvL2=12m2gr+2mgrvL2=6grvL=6grThus, speed at the lowest point of the vertical circle is 6gr.

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