A body is subject to a constant force F=i-2j+3k. What is the work done by the force in moving the body through a distance of 4m along x-axis & 3m along y-axis. Share with your friends Share 2 Somnath Mazumder answered this Here,F→=i^−2j^+3k^displacement of 4m along x axis is =4i^displacement of 3m along y axis is = 3j^Resultant displacement will bes→=4i^+3j^ Work done by the constant force F→ will beW=F→.s→=>W=(i^−2j^+3k^).(4i^+3j^+0k^ )=>W=1×4+(−2)×3+3×0=>W=4−6=−2 units of work 2 View Full Answer