A body is subject to a constant force F=i-2j+3k. What is the work done by the force in moving the body through a distance of 4m along x-axis & 3m along y-axis.

Here,F=i^2j^+3k^displacement of 4m along x axis is =4i^displacement of 3m along y axis is = 3j^Resultant displacement will bes=4i^+3j^ Work done by the constant force F will beW=F.s=>W=(i^2j^+3k^).(4i^+3j^+0k^ )=>W=1×4+(2)×3+3×0=>W=46=2 units of work

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