a body moving with uniform retardation covers 3km before the speed is reduced to half of its initial value. It comes to rest in another distance of how many metres?

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Retardation is uniform = a
let initial velocity = v
final velocity = v/2
distance travelled = 3 m
V2-u2 = 2asv24 - v2 = 2a×3-3v24 = 6aa = -v28 km/s2

Now in the second case
initial velocity = v/2
final velocity = 0
let distance travelled = x
we get-v24 = 2axon substituting the value of a we get x = 1 km

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