A body of mass 2 kg is acted upon by two forces 2N and 5N in the dorection of i^+j^ and j^ - k^ respectively. Of the body is displaced ffrom (3, -2, 1) to (-1, 2, 3) then work done is? Ans is 5 √2. Please explain how?

Dear Student,

Kindly find below the answer of your asked query.


$$\begin{gathered} F_1=i+j \\ {F}_2=j-k \\ {d}_1 = initial position = 3i-j+k \\ final position d_2=-i+2j+3k \\ net force F = F_1+F_2=i+j+j-k=i+2j-k \\ d is the net displacement=d_2-d_1=-i+2j+3k-(3i-j+k)=-4i+3j-2k \\ work done = F.d = \left(i+2j-k\right).\left(-4i+3j-2k\right)=-4+6+2=4 Joule \\ Net work done is 4 J. \\ This must be the answer. \\ I suggest you to please check the question once again and do get back to us because simple calulation says this answer only. \end{gathered}$$
Hope this information will clear your doubt about work done.
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