a body of mass hundred grams is at rest on a smooth surface a force of 0.2 Newton acts on it for 5 seconds calculate the distance travelled by the body

Dear Student
 

F = ma

a = F/m

here,

F = 0.2 N

m = 100 g = 0.1 kg

so,

a = 0.2 / 0.1

thus, acceleration

a = 2 m/s2

now,

s = ut + (1/2)at2

here,

u = 0

a = 2 m/s2

t = 5 s

so,

s = 0 + (1/2)x2x52

thus, the distance travelled will be

s = 25 m

Regards

  • 0
What are you looking for?