a body of mass hundred grams is at rest on a smooth surface a force of 0.2 Newton acts on it for 5 seconds calculate the distance travelled by the body
Dear Student
F = ma
a = F/m
here,
F = 0.2 N
m = 100 g = 0.1 kg
so,
a = 0.2 / 0.1
thus, acceleration
a = 2 m/s2
now,
s = ut + (1/2)at2
here,
u = 0
a = 2 m/s2
t = 5 s
so,
s = 0 + (1/2)x2x52
thus, the distance travelled will be
s = 25 m
Regards