a body of mass m is projected from ground with speed u at an angle theta with horizontal. the power delivered by gravity to it at half of maximum height from ground is

Dear Student,


the force acting on the particle is downward by the gravity and the body is moving upward hence the workdone by the gravity is -ve .total WD=-mgHmax=-mu2sin2θ2time taken to reach maximum height t=usinθgpower=-mu2sin2θ2usinθg=-musinθ2gREgards

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