a body of mass m is projected from ground with speed u at an angle theta with horizontal. the power delivered by gravity to it at half of maximum height from ground is Share with your friends Share 6 Shobhit Mittal answered this Dear Student, the force acting on the particle is downward by the gravity and the body is moving upward hence the workdone by the gravity is -ve .total WD=-mgHmax=-mu2sin2θ2time taken to reach maximum height t=usinθgpower=-mu2sin2θ2usinθg=-musinθ2gREgards -100 View Full Answer