a body of uniform cross sectional area floats in a liquid of density thrice its value . the portion of exposed height will be x. then calculate x*6 Share with your friends Share 1 Srikrushna S.nagargoje answered this seems question is very long! -3 View Full Answer Akshat Mishra answered this 1/3 = ratio of density of body to the density of liquid Area is uniform 1-1/3=2/3=height exposed -1 Hansika. answered this 2/3 -1
