a body released from the top of the tower of height h takes T seconds to reach the ground. The position of the body at T/4 seconds is ?

the acceleration of the ball will be g. Initial velocity will be 0 m/s in T sec. body travels h m.

By applying equations of motion we get

s= ut +1/2gT²

h = 1/2gT² ------[1]

in T/4 sec 

so, height will be

h₁ = (1/2).g.(T ²/16) -------[2]

from [1] and [2] we get h₁ =h/16 distance from point of release.

therefore distance from ground is =  h - h/16

thus,

height = (15/16)h