A body starts from rest and acquires a velocity V in time T. The work done on the body in time t is proportional toA) Vt/tB) Vsquare tsquare/ TC)Vsquare tsquare/ T

Here,

V = 0 + aT

=> a = V/T

So, at any time ‘t’ the velocity is,

v = 0 + at

=> v = (V/T)t

So, KE of the body after time t is,

KE = ½ mv^{2}

=> KE = ½ m[(V/T)t]^{2}

We know, work done is equal to gain in KE

So, Work done = ½ m[(V/T)t]^{2}

Thus, work done is proportional to [(V/T)t]^{2}.

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