A body starts from rest and acquires a velocity V in time T. The work done on the body in time t is proportional toA) Vt/tB) Vsquare tsquare/ TC)Vsquare tsquare/ T
Here,
V = 0 + aT
=> a = V/T
So, at any time ‘t’ the velocity is,
v = 0 + at
=> v = (V/T)t
So, KE of the body after time t is,
KE = ½ mv2
=> KE = ½ m[(V/T)t]2
We know, work done is equal to gain in KE
So, Work done = ½ m[(V/T)t]2
Thus, work done is proportional to [(V/T)t]2.