A BODY THROWN HORIZONTALLY FROM THE TOP OF THE BUILDING WITH A VELOCITY OF 10 m/s FALLS 30 m AWAY FROM THE BUILDING . WHAT IS THE HEIGHT OF THE BUILDING? (g=9.8)

Understand that the equation of the projectile is given by
y=xtanθ-gx22u2cos2θ
Now substitute
x=30u=10θ=0
Hence
y=30tan0-10×3022×102cos20y=-10×9002×100y=-45 m

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R= u [root over 2h/g]On substituting the values , find h:h= approximately 44 or (44.1)
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