A BODY THROWN HORIZONTALLY FROM THE TOP OF THE BUILDING WITH A VELOCITY OF 10 m/s FALLS 30 m AWAY FROM THE BUILDING . WHAT IS THE HEIGHT OF THE BUILDING? (g=9.8) Share with your friends Share 0 Peter Fernandes answered this Understand that the equation of the projectile is given by y=xtanθ-gx22u2cos2θ Now substitute x=30u=10θ=0 Hence y=30tan0-10×3022×102cos20y=-10×9002×100y=-45 m 1 View Full Answer Jyothi Priya answered this R= u [root over 2h/g]On substituting the values , find h:h= approximately 44 or (44.1) -1