a body thrown vertically up with initial velocity 52 m/sec from the ground passes twice a point at H height above at an interval of 10 s . The height H is (Take g= 10)

*u*= 52 m/s

*s*=

*ut*+ $\frac{1}{2}$

*gt*

^{2}

*s*= 520 + $\frac{1}{2}$($-$10

*)*(10)

^{2}

*s*= 520 $-$ (5

*)*(10)

^{2}

*s*= 520 $-$ 500 = 20 m

Given that

*s*= 2

*H*

2

*H*

*=*20 m

$\Rightarrow $

*H =*10 m

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