A box contains 10 green balls and 8 yellow balls . In how many ways two balls of the same colour can be drawn ?
dear student,
the formula for selecting "r" number of objects from "n" number of objects is
nCr =n!/r!(n-r)!
Number of ways of selecting two balls from 10 + 8 = 18 balls is 18C2=18!/2!(18-2)!=18*17*16...2*1/2*1(16*15*...2*1)=18*17/2=306/2 =153
similarly.
Number of ways of selecting two green balls from 10 green balls = 10C2 =45
Number of ways of selecting two yellow balls from 8 yellow balls = 8C2= 28
Favorable ways = 45+28=73
the formula for selecting "r" number of objects from "n" number of objects is
nCr =n!/r!(n-r)!
Number of ways of selecting two balls from 10 + 8 = 18 balls is 18C2=18!/2!(18-2)!=18*17*16...2*1/2*1(16*15*...2*1)=18*17/2=306/2 =153
similarly.
Number of ways of selecting two green balls from 10 green balls = 10C2 =45
Number of ways of selecting two yellow balls from 8 yellow balls = 8C2= 28
Favorable ways = 45+28=73