A box of mass 4kg is placed on a wooden planck of length 1.5m lying on the ground.The planc is slowly lifted from one end up to a vertical height of 0.5m at which point the box begins to fall down.Calculate coefficient of friction.

Given: m = 4 kg, distance(s) = 1.5 m , h = 0.5 m 
when the box just begins to slide mgcosθ=R, mgsinθ =μR which implies thatmgsinθ = μmgcosθμ=tanθ=hs2-h2=0.5(1.5)2-(0.5)2=0.52=0.3536

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