A Boy read 3/8 of the book on one day and 4/5 of the remainder on the other day if there were 30 pages unread,how many pages did the book contain?

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Let the total no. of pages be 'b'

Fraction of book read on Day 1 - 3b/8

Remainder - b - (3b/8) = 5b/8

Fraction of book read on Day 2 - (5b/8)(4b/5) = (20b/40) = b/2

Remainder = b - { (3b/8) + (b/2) } = b - { (3b + 4b)/8 } = b - (7b/8) = b/8

Given b/8 = 30 pages 

Therefore, b = 30 * 8 = 240 pages

  • 25

nice answer @niyor 

  • 0

clap hands

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