A boy standing on the ground and flying a kite with 100m of string at an elevation of 30°. Another boy is standing on the roof of a 10m high building and is flying a kite at an elevation of 45 °. Both the boys are on the opposite sides of the kites. Find the length of the string that the second boy must have so that the two kites meet.

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Dear Student!

Here is the answer to your query.

 

 

Let C be the position of the kite and A, B be the position of first and second boy respectively.

Let the length of the string (CD) with second boy be x metres.

 

In ∆ABC

 

Now CF = BC – BF = 50 m – 10 m = 40 m ( ∵ BF = DE = 25 m)

 

In ∆CFD

 

Hence the length of the string second by must have is metres.

 

Cheers!

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