A boy standing on the ground and flying a kite with 100m of string at an elevation of 30°. Another boy is standing on the roof of a 10m high building and is flying a kite at an elevation of 45 °. Both the boys are on the opposite sides of the kites. Find the length of the string that the second boy must have so that the two kites meet.



Dear Student!

Here is the answer to your query.



Let C be the position of the kite and A, B be the position of first and second boy respectively.

Let the length of the string (CD) with second boy be x metres.




Now CF = BC – BF = 50 m – 10 m = 40 m ( ∵ BF = DE = 25 m)




Hence the length of the string second by must have is metres.



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