A brass rod of 0 2 kg at 1000C is dropped into 0 5 kg of water at 200C - Physics - Heat

Question

A brass rod of 0 2 kg at 1000C is dropped into 0 5 kg of
water at 200C The final temperature of the mixture is
230C Calculate the specific heat capacity of brass(given
specific heat capacity of water= 1cal/gm0C)

Vaibhav T. · Accepted Answer

Dear Student,

The water will heated while the rod brass will be cooled
 We can write the heat balance equation,mwcwT-tw=mbcbtb-Twhere, mw=mass of watercw=specific heat capacity of watertw=temperature of watermb=mass of brasscb=specific heat capacity of brasstb=temperature of brassT=final temperature of mixturecw=4200 J/kg°Ccb=mwcwT-twmbtb-Tcb=0
5×420023°-20°0 2×100°-23°cb=409
09 J/kg°C

A brass rod of 0.2 kg at 1000C is dropped into 0.5 kg of water at 200C. The final temperature of the mixture is 230C. Calculate the specific heat capacity of brass(given specific heat capacity of water= 1cal/gm0C).

A brass rod of 0.2 kg at 100⁰C is dropped into 0.5 kg of water at 20⁰C. The final temperature of the mixture is 23⁰C. Calculate the specific heat capacity of brass(given specific heat capacity of water= 1cal/gm⁰C).