A bucket contains 8 kg of water at 25 degrees Celsius and 2 kg of water at 80 degrees Celsius is poured into it. Neglecting the heat absorbed by the bucket, calculate the final temperature of water.

Given m₁ = 8kg, T₁ = 25 , m₂ = 2 kg, T₂ = 80, let the final temperature = x

Heat lost by water =$2\times 4186\times (80-x)$
heat gain by water = $8\times 4186\times (x-25)$
2 *(80-x) = 8 *(x-25)
80-x = 4(x-25)
80-x =4x-100
5x = 180
x = 36 degree celsius