This is your answer-
We know that for an electric appliance
P = V2/R
or resistance will be given as R = V2?/ P ?
So,
P = 110w
V = 330 volts
R = 3302?/ 110
= 108,900/110 = 990
thus, resistance of the bulb is 990
now, electric energy consumed will be
E = number of units x power of each unit x time ?= n x P x t
n = 3
P = 110 W
t = 5 hours
so,
E = 3 x 110 ? 5
thus,
E = 1650Wh
..
the total cost of electricity = total unit of energy consumed x cost per unit
= 1650 x 0.7 Rs
thus,
total cost= 1155rs.
and
?monthly cost = total daily cost x number of days in month
=
1155rs. ? 30 = 34,650rs.