A bullet fired into a fixed target loses half of its velocity after penetrating 1 cm how much further will it penetrate before coming to rest assuming that it faces constant resistance to motion

Dear student,
Let initial velocity of the bullet = u
After penetrating 1 cm its velocity becomes = u/2
From v² = u² - 2as
(u/2)² = u² - 2as
Thus, a  = 3u²/8
Let further it will penetrate through distance x and stops at some point
.0 =  (u/2)² - 2 (3u²/8)x
Therefore, x = 0.33 cm

Regards