A bullet having a massof 10 g and moving with a speed of 1.5 m/s,penetrates a thick wooden plank of mass 900 g .The plank was initally at rest .The bullet gets embeddle in the planks and both moves together. Determined the velocity

Dear STudent,

(2) Mass of a bullet, m = 10 g = 0.01 kg

Speed of bullet, v = 1.5m/s

Mass of wooden plank, M = 90 g = 0.09 kg

Let the speed of plank containing plank be V.

According to the law of conservation of momentum,

Total momentum before collision = Total momentum after collision

⇒ mv +M0 = (M+m)V

⇒ 0.011.5 = (0.09+0.01)V

⇒ 1.5 = 10V

⇒ V = 0.15 m/s

Regards