A bullet of mass 0.02 kg is fired from a gun weighing 7.5 kg. If the initial velocity of the bullet is 200 m/s, calculate the speed with which the gun recoils. Share with your friends Share 0 Anshu Agrawal answered this Solution: plying the law of conservation of linear momentumMgunVgun+mbulletvbullet =0So 7.5×Vgun +0.02×200 =0or Vgun or recoil velocity =-0.02×200 7.5 =- 0.533m/sThe negative sign shows the gun's velocity is in the opposite direction from the bullet's velocity. 0 View Full Answer