A bullet of mass 0.02kg is fired from a gun weighing 7.5 kg .if the initial velocity of the bullet is 200 m/ s ,calculate the speed with which the gun recoils.

According to the law of conservation of momentum:

Mass of bullet x Velocity of bullet=Mass of gun x Recoil velocity of gun

0.02 x 200=7.5 x recoil velocity of gun

Recoil velocity of gun=0.02 x 200/7.5=0.53 m/s

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Mass of bullet, m1=0.02 kg
Velocity of Bullet, v1=200 m/s
Mass of gun, m2=7.5 kg
Recoil Velocity of gun, v= ?
m1v1=m2v2
0.02*200=7.5*v2
4/7.5=v2
0.533=v2

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