A bullet of mass m moving with velocity v strikes a block of mass M at rest and gets embeded - Physics - Work Energy and Power

Question

A bullet of mass m moving with velocity v strikes a block of mass M
at rest and gets embeded into it The kinetic energy of the
composite block will be,

Sanjay Singh · Accepted Answer

Dear student
Applying conservation of linear momentum for the block and the bulletinitial momentum Pi=mv+0let after the collision velocity of the combined system becomes v1Final momentum Pf=(m+M)v1so Pi=Pfmv=(m+M)v1v1=mv(m+M)kinetic energy ofthe composite system is K=12(m+M)v21=12(m+M)(mv(m+M))2K=12(m+M)(mv(m+M))2=12m2v2(m+M)Regards

A bullet of mass m moving with velocity v strikes a block of mass M at rest and gets embeded into it. The kinetic energy of the composite block will be,