(a-c) (-a+c). solve them using suitable identity

Dear student,

(a - c)*(-a + c) = a(-a + c) - c(-a + c) = -a² + ac +ac - c² = -a² + 2ac - c² = -(a² - 2ac + c²) = -(a - c)²

Regards

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a[-a+c]*-c[-a+c]
=-a+c*a-c
 
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=ac
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(a-c)(-a+c)= a(-a+c)-c(-a+c)
= -a2+(-ac)-(-ac)+c2
= -a2-ac+ac+c2
= -a2+c2
 
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a[-a+c]*-c[-a+c]
=-a+a*a-c
  • -1
Hmm
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