a canon is to fire up to 500 m horizontally.what should be the angle of projection , if the shells are fired witha velocity of 100 m/s?(g=10 m/s2)​

Dear Student,

R=u2sin2θg=100×100×sin2θ10sin2θ=R×10100×100500×10100×100=122θ=30θ=15


Regards,
Manoj Singh

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