A capacitor of capacity 2 microfarad is charged to a potential difference of 12 volt. It is then connected across an inductor of inductance 0.6 mH. What is the current in the circuit at the time when the potential difference across the capacitor is 6v?

Dear Student
since there is no resistor in circuit hence total energy is conserved 
Initial energy of capacitor= final energy of capacitor +final energy of inductor12CV12 =12CV22 +12LI2   { here V1 =12volt and  V2=6volt}CV12 -CV22 =LI2I2=C(V12 -V22)LI=C(V12 -V22)L=2×10-6(144 -36)0.6×10-3=36×10-6+3+11=0.6A

regards

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