a car initially at rest picks up a velocity of 72 km per hour in 15 seconds calculate acceleration and distance covered by the car

Dear Student , Given
u=0  ,  v=72 km/hr =20 m/s , according to the first equation of motion, v= u+at
So 20 = 0 +a*15  ie. a = 4/3 m/s2
Now distance  covered by second equation of motion ,S = ut + 1/2 at2
so  S= 0*15 +1/2 *4/3 * 152 ie S =  150 m
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