A car of mass 1 metric ton starts from rest and accelerates at a speed of 72km/h in 20 seconds. It the moves with a constant velocity of 80 sec and is brought to rest in next 10 sec.What is the total distance covered by the car in the entire journey Share with your friends Share 1 Anshu Agrawal answered this Dear student, Here, m=1 metric ton=1000kg u=0,v=72km/h=72×100060×60s=20m/s t=20s (i) From 0 to 20sec a=v−ut=20-020=1m/s2Distance covered in this part = 0.5×a×t2 =0.5×1×202=200m (ii) From 20sec to 100 secDistance covered with constant velocity = 20×80 =1600m(iii) From 100 to 110 seca=v−ut=0-2010=-2m/s2S =u22a=4002×2 = 100m( as v = 0)So total distance = 200+1600+100 =1900m Regards -2 View Full Answer God Father answered this Hiii -1