A car of mass 2000 kg travelling with a uniform velocity of 2 m/s accelerates till its velocity becomes 22 m/s. The work done on the car is.

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Dear student
from first law of motion v=u+at
                    v = 22m/s   u = 2m/s   t =1s (as it is travelling with uniform velocity which means same velocity in equal interval of time i.e. 1s)
                    
                         a = v-u = 20m/$s^2$
  as mass = 2000 kg     force F = ma = 2000(20) =40000N
     work done by the body ,W = F.s 
       from third law of motion   $$\begin{gathered} v^{2 }-u^2 = 2as \\ 484 -4 = 40s \\ s = \frac{480}{40}=12m \end{gathered}$$
    W = F.s = 40000(12) = 480000 joule.
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