a certain compound contains only C and O.Analysis shows it has 36% carbon and 64% oxygen.If its molecular mass is 400,then what is the molecular formula of compound?
relative no. of moles of C = 36/12 =3
relative no. of moles of 0 = 64/16= 4
simplest molar ratio = 3:4
Empirical formula =C304
Empiral formula mass =12×3+16x4=100
n=molar mass /empirical formula mass
=400/100 = 4
Hence , molecular formula = C3nO4n
= C12016
relative no. of moles of 0 = 64/16= 4
simplest molar ratio = 3:4
Empirical formula =C304
Empiral formula mass =12×3+16x4=100
n=molar mass /empirical formula mass
=400/100 = 4
Hence , molecular formula = C3nO4n
= C12016