A charge "q" is placed at the centre of the cube of side "l" What is the electric flux - Physics - Electric Charges And Fields

Question

A charge "q" is placed at the centre of the cube of side "l"
What is the electric flux passing through each face of the
cube?

Vijay Yadav · Accepted Answer

According to Gauss's Law,

$\oint \vec{E} . \vec{d s} = \frac{q}{ϵ_{0}}$ ............................(1)

Cube has six equal faces, so electric flux pass through each would be equal.

If A = area of face

and E = field intensity.

Then total flux = 6(E*A) = q/ε₀

So, net electric flux passing through each face of the cube is given by

$E * A = \frac{q}{6 ϵ_{0}}$

A charge "q" is placed at the centre of the cube of side "l". What is the electric flux passing through each face of the cube?