a child with mass m is standing at the edge of a disc with moment of inertia I,radius R,and initial angular velocity w(omega) the child jumps off the edge of the disc with tangential velocity v with respect to ground. then what is the new angular velocity

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Initial total angular momentum of the system=I+mR2ωwhen the child jumps off the edge with tangential velocity v it gives angular momentumto the disk =mvRAfter the jump of the child the total angular momentum=Iω'+mvrand by conservation of angular momentumIω'+mvr=I+mR2ωIω'=I+mR2ω-mvrω'=I+mR2ω-mvrI

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