In the figure, BC is the chord which is equal to the radius.

Chord BC subtends angle BOC at the centre O , It subtends angle CAB at a pt on the major arc, and it subtends angle CDB at a pt on the minor arc.

In triangle COB

BC = OB = OC (radius)

Hence triangle **COB is equialteral****. In an equilateral triangle, all the angles are equal and are 60 degrees.**

**hence, angle COB = 60**

**angle CAB = 1/2 ( angle COB) ( CAB is the inscribed angle of minor arc BC)**

= 60/2 = 30

angle CDB = 1/2/( reflex COB) ( CDB is the inscribed angle of major arc CB )

= 1/2( 360 - 60)

= 1/2 (300)

= 150

Hence the angle subtended on the major arc is 30 and the angle subtended on the minor arc is 150