A chord of a circle of radius 12 cm subtends an angle of 120° at the centre. Find the area of the corresponding segment of the circle. please explain me in easy way?
Draw a perpendicular OV on chord ST. It will bisect the chord ST.
SV = VT
In ΔOVS,
Area of ΔOST
Now, Area of sector OSUT
∴Area of segment SUT = Area of sector OSUT - Area of ΔOST=150.72-62.28
⇒Area of segment SUT = 88.44