A chord of circle of radius 10 cm subtends a right angle at the centre.Find the area of the corresponding minor segment and hence find the area of the major sector?
Let r be the radius of the circle and θ be the angle subtended by the chord at the centre.
Given, r = 10 cm and θ = 90°
Area of the minor segment
= Area of sector OAPB – Area of ∆AOB
Area of the major sector OAQB
= Area of circle – Area of sector OAPB