A circle of constant radius 'a' passes through origin 'O' and cuts the coordinate axes in points P and Q, then the equation of the locus of the foot of perpendicular from O to PQ is
(a) (x^2+y^2)(1/x^2+1/y^2)=4a^2
(b) (x^2+y^2)(1/x^2+1/y^2)=a^2
(c) (x^2+y^2)^2(1/x^2+1/y^2)=4a^2
(d) (x^2+y^2)(1/x^2+1/y^2)=a^2

Given a circle with constant radius 'a' passes through origin O and cuts the co ordinate axes at Q and P

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