A circle with radius R and center O is drawn . 2 tangents PQ and PR are drawn from point P and PO is twice the radius. Prove that PQR is an equilateral triangle



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PLEASE BRO MAKE DIAGRAM BECAUSE I HVEN'T ENOUGH RESOURCES TO MAKE IT
QO/PO = r/2r = 1/2 AND (SIN 60 = 1/2 ) SO QPO = 60 degree and PQ=PR SO ALL ARE 60 DEGREE AND SO PQR IS A EQUILATERAL TRAINGLE
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