A circular coil of radius 0.1m of number of turns 100, carries a current of 1.2A. Find the magnetic field a) at the centre of coil, b) at a point distance 0.2m from centre on the axis. Share with your friends Share 0 Ravi Gupta answered this Bcentre = Nμ0I2r=100×4π×1.2×10-72×0.1=7.5×10-4 TeslaBaxis =Nμ0I2r2(x2+r2)3/2 = 100×4×3.14×10-7×1.2×0.1×0.120.22+0.123/2=7.536×10-70.01=7.536×10-5Tesla 6 View Full Answer