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A coil having an area of cross section 0.05 m2 and number of turns 100 is placed at right angles to a magnetic field of strength 0.08 T. How much emf will be induced in it , if the field is reduced to 0.04 T in 0.01s?​

Dear Student, 
Please find below the solution to the asked query: 
E=NAdBdt   =100×0.05×0.08-0.040.01   =20 V
Hope this information will clear your doubts about Induced emf.                      
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given data:

A=0.05 sq m
n=100
B1=0.08T
B2=0.04T
t=100s

Initial flux = B1.A = 0.08×0.05 = 0.004wb
Final flux = B2.A = 0.04×0.05 = 0.002wb
(cos p = 1, as p=0)

emf= -d(flux)/dt
= -(0.002-0.004)/0.01
= 0.002/0.01
= 0.2 V
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