a coil having L = 2 mH current flowing through it is I = t2 e-t then the time at which emf become 0
emf = L(dI/dt)
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0 = 2x10-3 [d(t2 e-t)/dt]
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differentiate by product rule
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t2 (-e-t ) + 2te-t = 0
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2te-t = t2 e-t
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2t = t2
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t = 2 second
a coil having L = 2 mH current flowing through it is I = t2 e-t then the time at which emf become 0
emf = L(dI/dt)
-
0 = 2x10-3 [d(t2 e-t)/dt]
-
differentiate by product rule
-
t2 (-e-t ) + 2te-t = 0
-
2te-t = t2 e-t
-
2t = t2
-
t = 2 second