a coil having L = 2 mH current flowing through it is I = t2 e-t then the time at which emf become 0

emf = L(dI/dt)

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0 = 2x10-3 [d(t2 e-t)/dt]

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differentiate by product rule

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t2 (-e-t ) + 2te-t = 0

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2te-t = t2 e-t

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2t = t2

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t = 2 second

  • 91

emf = L(dI/dt)

-

0 = 2x10-3 [d(te-t)/dt]

-

differentiate by product rule

-

t2 (-e-t ) + 2te-t = 0

-

2te-t = t2 e-t

-

2t = t2

-

t = 2 second

  • 5
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