A concave mirror of focal length 15cm forms an image having twice the linear dimensions of the object. The position of the object when the image is virtual will be. (i) 22.5 cm. (ii) 7.5 cm. ( iii) 30 cm. (iv) 45 cm.

Dear Student,f=-15 cm , m=2m=-vu=2v=-2u1v+1u=1f1-2u+1u=1-1512u=-115u=-7.5 cm hence the position of the object must be 7.5 cm from the mirror .Regards

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