A concave mirror produces a magnification of +4 . The object is placed:
(a) at the focus
(b) between focus and centre of curvature
(c) between focus and pole
(d) beyond the centre of curvature
Also state the reason for your answer.
Given that,
m=h2/h1= - v/u=+4
It means that image is virtual and erect.
In case of concave mirror, a virtual and erect image is formed only when an object is placed between pole and focus.
So, option (c) is correct.
m=h2/h1= - v/u=+4
It means that image is virtual and erect.
In case of concave mirror, a virtual and erect image is formed only when an object is placed between pole and focus.
So, option (c) is correct.