A concave mirror produces a magnification of +4 . The object is placed:

(a) at the focus

(b) between focus and centre of curvature

(c) between focus and pole

(d) beyond the centre of curvature

Also state the reason for your answer.

Given that,
m=h2/h1= - v/u=+4
It means that image is virtual and erect.
In case of concave mirror, a virtual and erect image is formed only when an object is placed between pole and focus.
So, option (c) is correct.

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