A conductor with rectangular cross-section has dimensions (a ? 2a ? 4a) as shown in figure. Resistance across AB is x, across CD is y and across EF is z.
Then (1) x = y = z            (2) x > y > z         (3) y > z > x             (4) x > z > y

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  • 21
y<z<x
 
  • 5
why for ef 2a is taken
 
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