a cone of radius 10 cm is divided into two parts by drawing a plane through the midpoint of its axis , parallel to its base . compare the volume of the two parts

let the height of the cone be H and the radius be R.

this cone is divided into two parts through the mid-point of its axis. therefore AQ=1/2 AP

since therefore triangle AQD is similar to the triangle APC.

by the condition of similarity

volume of the cone ABC=

 

volume of the frustum=volume of the cone ABC-volume of the cone AED

volume of the cone AED=

therefore

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