a conical tent is made of 4.5 m wide trapalin . vertical height of the conical tent is 4 m and base radius is3 m .find the lenght of the trapalin used ,assuming that 10 % extra material is required for stiching margins and wastage in cutting (take pie = 3.14)

Let r be the radius, h be the height and l be the slant height of the given conical tent , then we have:r = 3mh = 4mthen l = h2 + r2 = 42 + 32 = 5mHence, CSA of conical tent = π r l= 3.14 × 3 × 5 m2= 3.14 × 15 m2= 47.10 m2Area of extra material required= 10100 × 47.10 m2= 4.71 m2Then total area of tarpaulin required= 47.10 + 4.71= 51.81 m2Now breadth of tarpaulin = 4.5 mHence, length of tarpaulin = total area of tarpaulinbreadth = 51.814.5= 51.8192 = 51.81 × 29 = 103.629 = 11.51mHence, length of the tarpaulin = 11.51m.

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